TrivialSplits()
identifies trivial splits (which separate one or zero
leaves from all others); WithoutTrivialSplits()
removes them from a
Splits
object.
Arguments
- splits
An object of class
Splits
.- nTip
Integer specifying number of tips (leaves).
Value
TrivialSplits()
returns a logical vector specifying whether each
split in splits
is trivial, i.e. includes or excludes only a single tip or
no tips at all.
WithoutTrivialSplits()
returns a Splits
object with trivial
splits removed.
Examples
splits <- as.Splits(PectinateTree(letters[1:9]))
efgh <- Subsplit(splits, tips = letters[5:8], keepAll = TRUE)
summary(efgh)
#> 4 bipartition splits (3 trivial) dividing 4 tips, e .. h
#> 1234
#> 12 ****
#> 15 .***
#> 16 ..**
#> 17 ...*
#>
#> Tip 1: e Tip 2: f Tip 3: g Tip 4: h
TrivialSplits(efgh)
#> 12 15 16 17
#> TRUE TRUE FALSE TRUE
summary(WithoutTrivialSplits(efgh))
#> 1 bipartition split dividing 4 tips, e .. h
#> 1234
#> 16 ..**
#>
#> Tip 1: e Tip 2: f Tip 3: g Tip 4: h